Pipe-calculus: Difference between revisions

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<math>a^+ . s \rhd a^- . t = s \rhd t</math>
<math>a^+ . s \rhd a^- . t = s \rhd t</math>


If either the left or the right hand side argument is a choice, each branch of the left side is paired with each branch of the right side.
If any of the arguments is a choice, each branch of the left side is paired with each branch of the right side.


<math>r \mid s \rhd t \mid u = (r \rhd t) \mid (r \rhd u) \mid (s \rhd t) \mid (s \rhd u)</math>
<math>r \mid s \rhd t \mid u = (r \rhd t) \mid (r \rhd u) \mid (s \rhd t) \mid (s \rhd u)</math>
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