Pipe-calculus: Difference between revisions

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<math>a^+ . s \rhd b^- . t = \bot</math>
<math>a^+ . s \rhd b^- . t = \bot</math>


If any of the arguments is a choice, each fork of the left side is paired with each fork of the right side.
If any of the arguments is a choice, each branch of the left side is paired with each branch of the right side.


<math>r \mid s \rhd t \mid u = (r \rhd t) \mid (r \rhd u) \mid (s \rhd t) \mid (s \rhd u)</math>
<math>r \mid s \rhd t \mid u = (r \rhd t) \mid (r \rhd u) \mid (s \rhd t) \mid (s \rhd u)</math>
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